Improve this answer. I say ALL months as months can have 28 days (29 in a leap year), 30 days and 31 days which is why I wouldn't simply calculate the days between two dates. So, i need to unite them to one column to check if the time difference is lower the 5. DATE () Extract the date part of a date or datetime expression. The Overflow Blog An intuitive introduction to text embeddings. (date1 - date2)It should return 1 but as they consider it as a number so they return 70 instead of 1. Let’s factor it in! First, we will take the person’s birthday and will use the DATEADD( ) function. numeric-expression. The difference between two dates (in oracle's usual database product) is in days (which can have fractional parts). sample: SELECT months_between(column1,column2) FROM Table Share. This is going to be short:. This is the reason we cannot apply direct addition or subtraction on date. date_open END. How to calculate years of experience from date_of_hiring to till date in months of an employee using sql query. When a user enters JAN 2009 - I want the worksheet to show data from Jan, Feb, Mar, Apr, May and June (2009). SELECT DATEDIFF (YY, DateOfBirth, GETDATE ()) - CASE WHEN RIGHT (CONVERT (VARCHAR (6), GETDATE (), 12), 4) >= RIGHT (CONVERT (VARCHAR (6), DateOfBirth, 12), 4) THEN 0 ELSE 1 END AS AGE. DATEDIFF(Day, MIN(joindate), MAX(joindate)) AS DateDifferen. select S. The second parameter defaults to the current date. For formatting functions, refer to Section 9. 0 months apart:Asked 3 years, 4 months ago. Datediff (cast ('2020-08-01' as Date),Cast ('2020-07-31' as Date)) => 1. You have the option to change the data type there. ). Let’s see a few examples of SQL subtract date from the DATEADD function: In the below example, we are adding one month to the existing date ‘20220730’. Oracle equivalent to SQL Server/Sybase. user637544 Jun 1 2009 — edited Jun 1 2009. DATEDIFF SQL Server function. Modified 3 years, 4 months ago. Anybody help what is the equivalent of Dateadd and Datediff in DBeaver or anybody can convert this code in DBeaver. I suggest to use "months_between" function because it takes leap years into account (months_between wants 2 dates as parameters):. Currently I am only returning 1. This will return an interval that may look something like “1 year 2 months 3 days”. 15 between 2 values that are 1 year, 1 month and 15 days apart. proc sql noprint; create table daystoOverdue_list as select distinct business_object_rk , DateDiff (DAY, value_dt, Today ()) as value_dt from case_DataTable_d as tbl where tbl. When you subtract two dates in Oracle, you get the number of days between the two values. Month-difference between any given two dates: Have a look at the TIMESTAMPDIFF () function in MySQL. The expression is given to calculate the month’s difference between two dates, use the date diff expression as shown below. This field level rule lets you display the difference between two dates. 208333, so the value is correct! So now that we know how subtracting dates. DECLARE @date datetime2 = '2021-01-07 14:36:17. datediff() is not giving tHe result as I am working in Oracle. getMonth (); return m2 - m1 + 1; } EDIT: Since Java 8, there is a more. dividing by 365. Example 1: Fetching Employees who Joined Between Certain Dates. There is no datediff in Oracle. The schema is SYSIBM. @Bruno - If the data types are TIMESTAMP WITH TIME ZONE, the interval that results from subtracting the two should take care of any time zone/ daylight savings time conversion. g. Javascript. Extract a value of a date time field e. The difference between the specified dates. Take these examples: Example 1 Date 1: 10th March 2011 Date 2: 3rd Feb 2011 MONTHS_BETWEEN = 1. Oracle Help Center - MONTHS_BETWEENyou ca also use LAG analytical function to get the desired results as : Suppose below is your input table: id account_number account_date 1 1001 9/10/2011 2 2001 9/1/2011 3 2001 9/3/2011 4 1001 9/12/2011 5 3001 9/18/2011 6 1001 9/20/2011 select id,account_number,account_date, datediff(day,lag(account_date,1) over (partition by. it does not give me the records marked with a date '17-JAN-02'. Expressions that return a value of any of the following built-in data types: a date, a timestamp, a character string, or a graphic string. Currently, my code just returns zero on the right side of the decimal place. この番号を取得するには、次のいずれかの関数を使用: Today ()、TodateEx ()、GetFirstDate ()、GetLastDate ()、DateRoll ()。. If you omit it, the ROUND () function. FROM HR. Its answer is 2014-08-17. Currently, my code just returns zero on the right side of the decimal place. SELECT DATEDIFF(day, '2018-03-13', GETDATE()) AS "Difference in days"; On that basis, let me explain the three arguments required in the DATEDIFF function syntax. It operates according to the rules of the Gregorian calendar. Comparison with Excel DATEDIFF function. (CASE WHEN Trips. FromDate, r. (floor ( (Base_DateDiff + 1 + Start_WeekDay) / 7)) counts the number of saturdays. Date 2: 1st Feb 2011. Since the value does not equal an entire month the result is 0. Step 5: Change Sort column. For example, this function returns 1. This creates a bunch of months from the first date. DP_MONTH returns the distance between the months capturing the input dates. 11. (Oct 10, 2006 - June 14, 2005 = 69) In SQL Server, there is a function datediff with datepart 'q'/quarter which behaves as follows :--. for the month differnce the standard sql is DATEDIFF, in this function you must pass 3 params, if you must calculate the difference from 2 columns, c1 and c2, you must do this query SELECT DATEDIFF(month,c1 , c2) FROM T WHERE. 4 Answers. 2. DateValue > DateAdd (day,-3,getdate ()) doing this in this way makes your. Syntax¶ MONTHS. For DATEDIFF: date_or_time_expr1 and date_or_time_expr2 can be a date, time, or timestamp. g. The format argument is optional. You also wouldn't prefix a function name with the @ sign. 29 Answers. getMonth (); int m2 = date2. DATE is the main – or rather, original – datatype used in Oracle for holding dates. select *, cast ( (cast (begin_date as date) - cast (end_date as date) YEAR) as decimal (3,2)) AS year_diff from x. Getting the months and years between two dates using Datediff There is a round up issue with the Datediff function. DP_MONTH returns the distance between the months capturing the input dates. 1 Answer. The following query selects all rows with a date_col value from within the last 30 days: . CREATE OR REPLACE FUNCTION dateDiff ( p_dt1 IN DATE, p_dt2 IN DATE ) RETURN NUMBER IS BEGIN RETURN p_dt1 - p_dt2; END; datediff('MONTH', pr. I was given code via an SR but it doesn't work (I'm able to save the code but when I try to look at the sample data, it just says "error"). 1 + TRUNC (InstallDate) - TRUNC (InstallDate, 'IW') get 1 for mondays to 7 for sunday. For example, adding three months or 12 days to a starting date. (The valid formats 1,7,10,11 will be described later. DATEDIFF. If the dates are really timestamps, then this is easy - subtract them and the result is a day to second interval. It means that the DATEPART function returns the number of times the boundary between two units is crossed. And what date you want to get for example difference between dates 456 days it's mean: 1 year 3 month and several days. I want to convert this number to years,Months,and Days. You can use TIMESTAMPDIFF which returns the difference datetime_expr2 - datetime_expr1 in years, months, days etc. expression2: This is a datetime expression you’ll substract from expression1. Justin, the example which you gave, if that is the scenario I want the output as 1. Enter a date format string that describes the Date2 parameter. --Changing current database to the Master database allows function to be shared by everyone. Add six months to a start date. SYSDATE is already a date. Share. Modified 9 years, 7 months ago. from a date time value. This example returns the date of the next Sunday after January 1, 2000: SELECT NEXT_DAY ( DATE '2000-01-01', 'SUNDAY' ) FROM dual; Code language: SQL (Structured Query Language) (sql) It returns the following output: 02-JAN-00 Code language: SQL (Structured Query Language) (sql) Oracle doesn't have a DATEDIFF() function. The "DATEDIFF" and "Datepart" functions are used to determine years, months and days between two. AVERAGES CTE shows how to apply AVG function to. I want to select some data from one table if a date from another table is at least 6 months before today. create or replace function FUN_DATEDIFF ( dateFrom in date, dateTo in date, interval in char return number AS result number; beginThe default is zero (0). DOW: returns the day of the week, between Sunday (0) and Saturday (6) DOY: returns the day of the year. HQL Date format in Oracle / PostgreSQL: select TO_CHAR. January 30, 2022 5:11 PM / SQL. And determining if the date falls on a holiday (by querying against your holiday table) should be trivial. The datepart value cannot be specified in a variable, nor as a quoted string like 'month'. Therefore, if you’re looking for. Kilian Hekhuis. CREATE OR REPLACE FUNCTION datediff (p_what IN VARCHAR2, p_d1 IN DATE, p_d2 IN DATE) RETURN NUMBER /* Updated to reflect current database and PL/SQL functionality */ AS BEGIN RETURN (p_d2 - p_d1) * CASE UPPER (p_what) WHEN 'SS' THEN 24 * 60 * 60 WHEN 'MI' THEN 24 * 60 WHEN 'HH' THEN 24 ELSE NULL END; END;SELECT months_between ( date_1, date_2 )/12 years_between FROM employee. Voila! You've the the last day of the month containing your reference point in time. SELECT DATEDIFF(day,'2008-06-05','2008-08-05') AS DiffDate from dual is not working in SQL ERROR : ORA-00904: "DATEDIFF": invalid identifier 00904. . Adds days, months, and years to the date and returns the result. Returns NULL if either of <date_1> or <date_2> is NULL. Is there any simple way to calculate this in sql server 2005 . . Introduction. SELECT * FROM EmployeeAttendance WHERE DateJoined BETWEEN '2021-01-01' AND '2022-12-31'; This query will return all employees who joined between January 1, 2021, and December 31, 2022. So subtracting a TIMESTAMP WITH TIME ZONE that is 5 am Eastern from a TIMESTAMP WITH TIME ZONE that is 2 am Pacific will result in an interval of 0. DateDiff. date_to, DATEDIFF(DD, evnt. Returns a date string or the current date. Given two dates then the difference between them is a number of full calendar months and the remainder is the number of days (and hours, minutes and seconds) - this is easy to find using the MONTHS_BETWEEN function and some modulo arithmetic (see my. As shown clearly in the result, because 2016 is the leap year, the difference in days between two dates is 2×365 + 366 = 1096. I tried going off of something like this: Select records from SQL Server if greater than 6 months but I get the error: Subquery returned more than 1 value. ArrivalDate, Trips. It returns a whole month (no fraction) if both dates have the same day-of-month or. Table 9. DP_QUARTER returns the distance between the quarters capturing the input dates. Oracle SQL time difference in HH:MM:SS. Now for testing purposes I need to compare the data for the last say 4 months from the sysdate. See the valid date parts in. So, for example: WHERE date2 - date1 BETWEEN 60 AND 90. however using the below sql statement im getting. For example, suppose you have values below the start and end times. *Or even the CTIME. Funciones comúnmente utilizadas de Oracle: DateDiff devuelve una función personalizada para el intervalo entre dos fechas (Por supuesto, hay otros métodos para lograr, en ORACLE los tipos de fechas se pueden comparar directamente, y finalmente dar ejemplos de métodos). Converts one date format to a new format and returns the result. 2) format. Answer: You can use the months_between function and convert it easily yo years between and decades between two dates: months_between/12 = years between. 1. 5 days to a given date. Notice that the first row has a difference of 1. Sorted by: 10. If you enter a negative parameter, the system subtracts the specified days, months, or years. DECLARE @yourDate DATE = '20160229' select DATEADD (MONTH, DATEDIFF (MONTH, -1, @yourDate)-1, -1) Just a note: this does remove any time portion in the input date, which may or may not be desired. subtracting date literals as pure dates without conversion. by: sandy | last post by: Hi, Using Java script I am trying to create code where when you place in the start date it automatically calculates 6 months for the experations date. DATEDIFF (MONTH, DATEADD (DAY,-DAY (startDate)+1,startDate),DATEADD (DAY,-DAY (startDate)+1,endDate)) Share. 1 Answer. You can't use aliases you created in the SELECT clause elsewhere in the same SELECT clause, so you need to place your FIRST_VALUE() and LAST_VALUE() functions within the DATEDIFF() function:. 0. last_day (feb) to last_day (mar) is also commonly accepted as a "month". 9. 000000 1. As with day to second intervals, the format for this is fixed. 99. Tdy. Would give you rows where date2 (the later date) is 60 to 90 days later than date1. In MySql the syntax of DATEDIFF is different: DATEDIFF (date1, date2) and returns the difference date1 - date2 in days. DATEDIFF accepts either. You also wouldn't prefix a function name with the @ sign. Asked 7 years, 2 months ago. SELECT DATEADD(month, DATEDIFF(month, 0, @mydate), 0) AS StartOfMonth Share. 6. If I've got it right. The math is 100% accurate for dates within a couple of hundred years or so. And lastly: I would strongly recommend using the ISO-8601 date format YYYYMMDD (here:. When you multiply it by 24 (number of hours in a day), 60 (number of minutes in an hour) and 60 (number of seconds in a minute), the result is number of seconds (DIFF_SECS). Oracle Fusion Global Human Resources Cloud Service - Version 11. 2. Factor by 24 to get hours, 24*60 to get minutes, 24*60*60 to get seconds (that's as small as dates go). Because the months are 06 in both dates. Converting a raw number of days into a number of weeks and days is pretty simple. Thanks in advance for any help; this has been driving us crazy for a few months now. Teams. But it only for the date not for the time so i will be glad to know how to unite the two int columns + and convert it to date type for time difference. It means that the DATEPART function returns the number of times the boundary between two units is crossed. cust_field_nm eq "x_case_dte_dd" and datepart. Note that it is subtracting the second from the first, so you must have them in this order. Get Value for Last Month. date]-90) - my comparison subtracts 90 days from the max date Yes, I know,. It takes into account the fact that DATEDIFF() computes the difference without considering what month or day it is (so the month diff between 8/31 and 9/1 is 1 month) and handles that with a case statement that decrements the result. 6. g. SQL Server has a nice function called DateDiff which takes a date part, startdate and enddate. 指定した日付の差異。次の値が有効です。 DD: 差異を日数で計算します。. If month is the same in both dates: results for month is negative. Beneath the plainness of its name, it hides a little depth. Second option is wrong when start hours/minutes/seconds is less then end. 一重引用符で囲んだ'YYYY-MM-DD[*HH:MI[:SS]]'形式の文字列(*はコロン(:)または空白でも可)、または現在の日付を返す引用符なしの@DATENOW. AT TIME ZONE. Write queries for continuous periods as explicit range condition. TIMESTAMP Functions. The part to return. About; Products. Assuming that a. We would like to show you a description here but the site won’t allow us. I want something like this. Only 10+ years later - here's a db<>fiddle which demonstrates the difference between subtracting a date from a date (e. 0 is for 1/1/1900, and getdate is the current date --(i used a set date bc dates will change as this post gets older). Tarek Fathy Nov 18 2010 — edited Nov 18 2010. DAYS(date2 - date1). This question was incorrectly asked. you can check against last 90 days. @KanagaveluSugumar - An Oracle DATE always has a year, month, day, hour, minute, and second component. Table 9. The Oracle/PLSQL MONTHS_BETWEEN function returns the number of months between date1 and date2. Instead, use the dateAdd function on todays date, and compare the database table column to the result of that single calculation. Calculate difference between 2 date / times in Oracle SQL. datediff isn't a function in Oracle. select *, cast ( (cast (begin_date as date) - cast (end_date as date) YEAR) as decimal (3,2)) AS year_diff from x. hourBegin, a. I have a data field in my table that i would to use within my WHERE clause, to get the last 12 months dataset so for example, WHERE date between '20110323' and '20100323' Is this possible? I know I have to use something like GETDATE() or something but not quite sure how to incorporate this. It should be 24 months. Multiply by 24 -- hours, multiply by 60 minutes, multiply by 60 -- seconds. Instead, you can use simple arithmetic with Oracle dates, where subtracting one date from another gives the number of days, and where you can add an subtract days from a given date. 16. ArrivalDate, Trips. · User1416329745 posted ANSI SQL 1992. ). The DATEPART () function returns an integer value that represents a specified part of the date of a given date. A) Get the next weekday later than a date. date1. Getting the months and years between two dates using Datediff There is a round up issue with the Datediff function. For example, from 2/10 to 3/10 is considered one month, and from 2/10 to 3/15 is also considered one month. The first week of the year is 1. I need the Oracle equivalent to the SQL Server DATEDIFF function to compute the difference between two dates. getYear () * 12 + date2. If you subtract from one date other you will get a count of days between this two dates. 2. I have two Oracle columns (in a VIEW, not a table) - DateOfBirth and MembershipDate. 9. Oracle SQL Hours Difference between dates in HH:MM:SS. Sorted by: 3. 2903225806. Let’s see a few examples of SQL subtract date from the DATEADD function: In the below example, we are adding one month to the existing date ‘20220730’. In SQL, we can add or subtract days, months, or years to a date by using the DATEADD function. ReturnDate)) + ' days') ELSE CAST(DATEDIFF(day, Trips. =DATEDIFF ("d", Fields!startDate. Firstly, for example, it doesn’t really hold a date, instead it records a datetime. Can Any one help me please. I was following along with the toad workbook 101 video (Toad Data Point Workbook 101: The Ins and Outs) and really wanting to replicate the presenter's use of the date diff() function. Syntax @DATEDIFF (' difference ', ' date ', ' date ') difference. Few examples of DATEDIFF: DATEDIFF - Example 1 Here, in this example, datepart is "day": SELECT DATEDIFF(day,'2016-06-05','2016-08-05') AS DiffDate. The former produces a number representing the count of days between the two dates, while the latter produces an interval representation of the. Asked 9 years, 7 months ago. - Find the “date_diff” in minutes and add it with the “date_diff” in hours and the “date_ diff” in days. Order your results by the number of years employed. *You may also use the DATEDIFF function. MANAGER_ID, PROJECTED_DATE. The MONTHS_BETWEEN () function is used to get the number of months between dates (date1, date2). datediff; sysdate; Share. USE MASTER GO -. 0. I have a request to build a set of worksheets that accept an intial parameter - Start Date in the format MMM YYYY. Oracle Oracle Database Release 19 SQL Language Reference MONTHS_BETWEEN Syntax Description of the illustration months_between. You can even find the number of hours, minutes, seconds, and so on in terms of details in. date2 Syntax. In Oracle, dates are just numbers. 0. SQL Server ignores that this is just one day. Right-click and select Convert to Date. We will use the below date for the examples. e in the future) rather than 1992 as probably intended. Admission_Date) > 5. The DateDiff function returns how many seconds, months, years - whatever interval you specify between the first date (here 0) and the second date (here the current date). Simply i need to convert this: SELECT FLOOR(DATEDIFF(NOW(),`startdate`)/365. CREATE OR REPLACE FUNCTION datediff (p_what IN VARCHAR2, p_d1 IN DATE, p_d2 IN DATE) RETURN NUMBER /* Updated to reflect current database and PL/SQL. Remarks. 0. See the following conditions: If date1 is later than date2,. Modified 8 years ago. Also, you can check this for minutes : Oracle : how to subtract two dates and get minutes of the result. But your query is giving the last date of previous month. 9. 365 days elapse between the two dates. The DATEDIFF() function returns the number of days between two date values. unit: The unit can be one of the following options: FRAC_SECOND (microseconds), SECOND, MINUTE, HOUR, DAY, WEEK, MONTH, QUARTER, or YEAR. Try SELECT SYSTIMESTAMP + INTERVAL '5' MINUTE, SYSTIMESTAMP + 5 / 24 / 60 to convince yourself. Using datediff in oracle. DATEDIFF(interval, date1, date2) Parameter Values. Fractions are allowed; you can add 2. Push out all due dates by one week. answered May 15, 2013 at 7:21. , YEAR, MONTH, DAY,. If the month is in the future. 1. 000 READDATE < DATEADD(month, DATEDIFF(month, 0, GETDATE()) - 10, 0). SELECT FIRST_NAME, HIRE_DATE, SYSDATE, SYSDATE - HIRE_DATE. Date Part Flexibility: Years, months, days, hours, minutes, and seconds are among the date parts that are supported. In Oracle, MONTHS_BETWEEN(date1, date2) function returns the number of months between two dates as a decimal number. So I'm guessing it is an available function for mysql, but not for oracle databases. SELECT DATEADD ( quarter, DATEDIFF. Click on any table field/column. Functions, you can call DateDiffDay: var ans = from t in Table1 group t by 1 into tg select tg. The dates do not have to be in the same format in the extract file, but the format of each must be supported. 242199 assumes that you want the number of solar years between 00:00 on the first date and 00:00 on the second date, to 9 significant figures. CODE = 'CONTACT_CLIENT' THEN a. Viewed 2k times. Consider SQL Server function to calculate the difference between 2 dates in months: SQL Server : -- Difference between Oct 02, 2011 and Jan 01, 2012 in months SELECT DATEDIFF ( month, '2011-10-02', '2012-01-01') ; -- Result: 3. 2 Answers. Viewed 3k times 0 I have table called C_Order. Here’s the syntax for the DATEADD function: DATEADD (interval, number, date); The interval. SELECT select AVG (months_between (SYSDATE,DOB)) AS AVERAGE_AGE_IN_MONTHS. datediff (q,start date,end date) i. MONTHS_BETWEEN gives the number of whole months between the 2 dates, and calculates the fractional part as the remainder in days divided by 31. The first one involves getting the difference in days and then converting it to 'x year y month z days'. Oracle and MySQL support the SQL92 function EXTRACT, as in EXTRACT(MONTH FROM whn). The screenshot below shows the data I want as well as the incorrect month between results I am obtaining. Function. How can we. , YEAR, MONTH, DAY,. If date1 is earlier than date2, then the result is negative. The syntax for using the DATEDIFF function in Google BigQuery looks like the following:. Extract a value of a date time field e. ExampleHere I need to calculate the difference of the two dates in the PostgreSQL. ) The dates and their formats are separated by a comma (,) and are defined in the Data field of the. My Oracle Support provides customers with access to over a million knowledge articles and a vibrant support community of peers and Oracle experts. If this format has been used to. date_from) = 1. Date. Parameter Description; interval: Required. ), the start date or time that specifies the beginning of the period to measure,. lastModified - w. SELECT AVG (CAST (DATEDIFF (d, DateUsed, DateExpires) AS FLOAT)) FORM tbl. Improve this answer. For example the difference between 1st March 2011 and 3rd March 2012 is 1. Getting the 1st day of the month is simpler: select dateadd (day,- (day (current_timestamp)-1),current_timestamp) From your reference point-in-time, subtract (in days), 1 less than the current day-of-the-month component. AT TIME ZONE. The syntax for the DATEDIFF function in SQL Server (Transact-SQL) is: DATEDIFF( interval, date1, date2 ) Parameters or Arguments interval. Share. OutSystems can use both Oracle and MSSQL as its primary database. floor(months_between(sysdate, dateofbirth)/12) But, months_between function treats end of month day specially. 99. Select DATEDIFF (MM,0,GETDATE ()) Output - 1374, If getdate () output is "2014-07-23 19:33:46. Here are the 10 federal holidays a year, almost one per month: New Year’s Day on January 1; Martin Luther King’s Birthday on the. 365 days elapse between the two dates. InDays)) % (Pattern. The days are in two different, adjacent months, so the answer is 1 month difference. Finally, we will use a CASE statement. The name of the order date month is printed, followed by the day of the month, a comma, and four-digit year. To get the months or years separately, use extract. January 1 of any year defines the starting number for the week datepart, for example: DATEPART (wk, 'Jan 1, xxxx') = 1, where xxxx is any year. References: ( found on on 05/15/2015 ) 1. 25) This seems to be another common approach - and was also given in a comment on my question. 2 -Increment by 1 into total months count -. DateDiffDay (r. Calculate how many years have passed: given year - 1900 2. I am looking for solution how to select number of days between two dates without weekends and public holidays. For the last row return the calculated date. SELECT --Start with total number of days including weekends (DATEDIFF (dd,@StartDate,@EndDate)+1) --Subtact 2 days for each full weekend (DATEDIFF (wk,@StartDate,@EndDate)*2) --If StartDate is a Sunday, Subtract 1 ELSE 0 END) --If EndDate is a Saturday, Subtract 1 FROM dual. Tip. 264k 58 58 gold badges 366 366 silver badges 409 409 bronze badges. Oracle also has its own enterprise modules and application server software. メンバーの日. SQL is also known as Structured Query Language. You could always create your own custom function in the module: Function MonthDiff (startdate, enddate) ' return number of months between two dates. . dp_monthは、入力日付を取得する月間の距離を返します。 (2006年10月) - 2005年6月= 16) dp_weekは、入力日付を取得する週間の距離を返します。 各標準カレンダ週は日曜日に始まり、7日にまたがるように定義されています。 (2006年10月10日 - 2005年6月14日= 69)The result only contains the year, month and day, not the time. If you like this article or if you have some. Oracle datediff function. 37. idUsage Notes¶. sql. It has been tested on a wide range of years (including leap ones) and more than 700k combinations of dates (including end of every months). g. COMPUTE days2 = DATEDIFF(date2,date1,"days"). The months_between function returns the elapsed months going from the second date to the first. It’s a seven byte store of century, year, month, day and hour, minute and second. Few examples of DATEDIFF: DATEDIFF - Example 1 Here, in this example, datepart is "day": SELECT DATEDIFF(day,'2016-06-05','2016-08-05') AS DiffDate Result: DiffDate 61 If the endDate has a day part less than startDate, it will get pushed to the previous month, thus datediff will give the correct number of months. What's the function in Oracle that would be the equivalent to DATEDIFF in the SQL Server? On Oracle, it is an arithmetic issue: Select DATE1. PROJECTID, PROJ_TASK. E. In this Document. DATEDIFF(datepart, startdate, enddate) Where datepart is a string that specifies the unit of time you want to use for the calculation (e.